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Genetics
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Добавлен 2 янв 2016
Short genetics videos used in a genetics course, BIS101, at the University of California at Davis. The videos were developed for a flipped format aimed at biology, biochemistry and genetics undergraduate students. I am Luca Comai, a professor of plant biology at UC Davis. I do research on plant genetics and genomics.
DNA properties: strand polarity, base pairing, Chargaff rule, and melting
This video explains what the 5' and 3' ends of DNA are, it teaches you how to recognize the DNA bases, how the DNA strands pair to form the double helix, how to understand Chargaff rule and to solve problems connected to it, and finally the process of DNA melting, i.e. denaturation, and separation of the DNA strands.
Просмотров: 808
Видео
Meselson Stahl
Просмотров 1882 года назад
The discovery of semiconservative DNA replication by Meselson and Stahl
CRISPR Biochemistry Part I
Просмотров 7004 года назад
This is an instructional video used in Luca Comai's general genetics course (BIS101) at UC Davis
CRISPR Biochemistry Part III
Просмотров 1,5 тыс.4 года назад
This is an instructional video used in Luca Comai's general genetics course (BIS101) at UC Davis
CRISPR Biochemistry Part II
Просмотров 1,7 тыс.4 года назад
This is an instructional video used in Luca Comai general genetics course at UC Davis
Introduction to bacterial sex
Просмотров 2,8 тыс.5 лет назад
This video introduces the ways through which bacteria share DNA, explains conjugation of plasmids, and the fate of DNA once in the recipient bacterial cell: replication, recombination, or loss.
Heritability and selection in breeding
Просмотров 21 тыс.6 лет назад
The video explains the meaning of narrow sense heritability (h^2), its derivation and use.
The complementation test
Просмотров 35 тыс.6 лет назад
This video explains why geneticists cross two mutants to determine if they are allelic, i.e. in the same gene. It explains the genetic and molecular basis of this test.
Sex determination by the Y chromosome
Просмотров 35 тыс.6 лет назад
This video will teach you how chromosome Y determines maleness in mammals. It covers studies with aneuploids, Y chromosome translocation, and the transgenic analysis of SRY. It also compares sex determination in mammals and fruit fly.
Sex determination: X-inactivation
Просмотров 10 тыс.6 лет назад
This video explains why one X chromosome is inactivated in females of mammals, how it happens during embryogenesis and what are the consequences. Did you know that you can count X chromosomes in a cell by looking at Barr bodies? It also explains why a calico cat has orange and black fur patches.
The discovery of sex chromosomes
Просмотров 5 тыс.6 лет назад
This video describes the discovery of sex chromosomes, how they pair and segregate producing two different types of gametes: those that make boys and those that make girls.
Meiosis: nondisjunction and aneuploidy
Просмотров 2,3 тыс.7 лет назад
Meiosis: nondisjunction and aneuploidy
Meiosis and life cycles
Просмотров 2,2 тыс.7 лет назад
When does meiosis take place in the life cycles of different organisms? It depends on the type of life cycle.
Meiosis: chromosome pairing and recombination
Просмотров 8 тыс.7 лет назад
Meiosis: chromosome pairing and recombination
DNAseI hypersensitive sites in chromatin
Просмотров 12 тыс.7 лет назад
DNAseI hypersensitive sites in chromatin
Assessing linkage with the Chi square test
Просмотров 4,2 тыс.8 лет назад
Assessing linkage with the Chi square test
Complementation and recombination in bacteriophages
Просмотров 45 тыс.8 лет назад
Complementation and recombination in bacteriophages
Finally, found this video and now i understand this❤thnk you so much
Great presentation! Thank you.
I love bacterial sex
You sound like Tyson Fury. Are you Tyson Fury?
The mice are females. Please, check the article: Kato T, Miyata K, Sonobe M, Yamashita S, Tamano M, Miura K, Kanai Y, Miyamoto S, Sakuma T, Yamamoto T, Inui M, Kikusui T, Asahara H, Takada S. Production of Sry knockout mouse using TALEN via oocyte injection. Sci Rep. 2013 Nov 5;3:3136. doi: 10.1038/srep03136. They are knockouts with Sry gene.
Great explanation!
No third sex. Only males or females thanks to SRY gene
This lecture is very helpful! Thank you so much!
Amazing
Thank you!
This has saved me, thank you!
Best video 📸 hats off for clean explanation
I'm a Vietnamese student but it's not so difficult to understand. Thanks you and hope more and more video.
Bakteriler çoğunlukla eşeysiz olarak, amitoz bölünme denen bir yöntemle ürerler. Bu, ilkel bir mitoz bölünme gibi düşünülebilir ve tek bir hücreden, birbirinin aynısı olan iki kopya üretilir. konjugasyon gen transferdir ama üreme değildir yani aralarında bir özelliği kendisinden birleştiği bakteriye gönderir. bu sayede her iki canlıda da aynı organel bulunur.
Amazing!
This is very useful. Thank you for creating this!
Excelent!
Great video, thank you so much
your explanation is too confusing. Either retire or get better at teaching.
It just....waooooooo sir.....💥💥💥💥💥💥💥💥
🥰🥰🥰❤❤❤
Can’t understand speak clearly thanks
i enjoyed how you enjoyed hide you systematically explained your points......getting something new
I found Naveen Patnaik's brother.. 😂
This makes me wanna hang myself
Love this video, thank you sir!
The following pedigree involves a single gene causing an inherited disease. If you assume that incomplete penetrance is not occurring, indicate which modes of inheritance are possible and which are not possible and why (Affected individuals are shown as filled symbols.) 1-1 1-2 DE 11-2 II-3 III-1 III-2 III-3 IV-1 IV-2 IV-3 [2] a) Recessive b) Dominant c) X-linked, recessive [2] I want answer please
Thanks! Regards from Iowa City.
Amazing video. My genetics class at Temple U. has failed to communicate the concepts of this 6 minute video in 3+ weeks of lecture AND in person lab, where as this video is an elegant, cogent recount of the concepts, and practices core to Benzer's momentous discoveries. I can not thank you enough for this video.
Wow I totally missed this great channel. Very great teaching! I wish you more fame in future & hope for more great interesting Videos of you :)
Thank you so much sir!
Thank you for the video. Explanation is awesome. It's very useful for students like us.
Helpful ! Thankyou .
Thanks a lot Professor for this valuable information
Really, this video is best. I learned the complementation test in Univ but I didnt get it. So I searched many writings and videos for it but I couldnt understand it well. Just after watching this video, I got it. Thanks so much🙂
You are most welcome
Respected sir, I need the answer f below question. No one know the answer if you know please give its answer. (Your company has a highly successful tomato cultivar. It is a hybrid between two inbred lines that you developed. Recent years, a cultivar similar to the hybrid cultivar emerged. The seed are very cheap, and the market f your cultivar started to dwindle. Sine it is a hybrid and you thought that the cultivar is well protected from thieves. However, the cultivar from the other company has no phenotypic differences from your cultivar. You started to think that the other company stole your cultivar. How will you collet the data before you sue the company? Be sure that your data are reliable and your logic has no flaw. Otherwise, judge will not rule in favor of your company. )
you actually gave me a conceptual understanding of epistasis, thank you so much
If the occurance of round pod shape is 3/4 and wrinkled pod shape is 1/4 Then, how total no of pods in a plant will be 5?
The probability of an event and how many tests you carry out are not related. The p of rolling 1 from a 6-face die is 1/6. You may roll the die once, twice, thrice and so on. The p of 1 for each roll is the same: 1/6. The fact that the pod has 5 seeds does not affect the p for each seed: 3/4 for the dominant phenotype, 1/4 for the recessive. You can derive the empirical probability if you carry out many tests. For example, if you roll a die 1000 times, you should obtain close to 166 instances of 1, or 1/6.
Francais
🤔
Very good explanation! Thank you very much! :)
Could you please explain to me why the P of D unlinked to M is 0.25^5 at 3:22?
D is the dominant allele for the disease condition. Let's call the M (marker) alleles M1 and M2. Remember that in each mating we are dealing with the probability of gametes from one parent, the carrier. The other parent is typically irrelevant because the disease condition is rare. In the absence of linkage, the P of a gamete with a given combination of alleles, such as D M1, from Dd M1M2 is 0.25. This is because the P of a D gamete is 0.5. Same for the P of an M1 gamete. Thus, 0.5 x 0.5 = 0.25. P of 0.25 is the same for each mating in the pedigree.
@@Genetics101 thank you so much <3
Thank you !
thx
dude this is the best!
TY
I didn't understand shit but thanks for your video
Very clear explanation!
Wow.. jaw dropping explanation
Glad you liked it
Awesome thank you i needed this